Key Ideas Review.

Okay,so I'm doing odds,and I think Karen is doing evens.

Pg.30-31

1.The Pythagorean relationship can be used to determine the length of the hypotenuse of a right triangle when the lengths of the two legs are known. AGREE?

3.Determine the length of the hypotenuse.Show your work.

a)

k² + j² = l²

40cm² + 9cm² = l²

(40² x 40²) + (9² x 9²) = l²

1600cm² + 81cm² = 1681cm²

√1681cm² = √l²

41cm²

b)

p² + q² = r² 12m² + 35m² = r² (12² x 12² ) + (35² + 35²) = r²

144m² + 1225m² = 1369m²

√1369m² = √r²

37cm²

5.Calculate the missing side length for each right triangle,to the nearest tenth of a centimeter.Show your work.

a)

w² + x² = y²

w² + 25² = 36²

11 = 25 - 36

√11 = 3.3

3.3²

b)

f² + g² = h²

7cm² + g² = 12cm²

49cm² + g² = 144cm²

144cm² - 49cm² = 95cm²

√95cm² = 9.7cm²

9.7cm²

7.A triangle is made up of two smaller congruent right triangles.

a)Find the Length of the hypotenuse for the right triangle,to the nearest tenth of a metre.Show your work.

4m² + 2m² = b²

(4 x 4) + (2 x 2) = b²

16m² + 4m² = b²

√20m² = 4.5m

b = 4.5m

b)Calculate the perimeter of the large triangle,to the nearest tenth of a metre.Show your work.

I don't know how to do this one..Help?

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