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20.3/2=r10.15=r (π.r.r)x h=v
(3.14 . 10.15 . 10.15) x 10=v
323.49065cm^2 x 10cm=v
3 234.9065cm^3=v
The Answer: 3 234.9065cm^3
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(3.14 . 10.15 . 10.15) x 10=v
323.49065cm^2 x 10cm=v
3 234.9065cm^3=v
The Answer: 3 234.9065cm^3
7.4
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M.I
* height = 10m
* diameter = 1 (outside) and 0.8 (inside)
* diameter = 1 (outside) and 0.8 (inside)
Outside : r = d/2 r = 1/2 r = 0.5 v = (π x r x r) x h v = (3.14 x 0.5 x 0.5) x h v = 0.78m^2 x 10m v = 7.8m^3 Inside : r = d/2 r = 0.8/2 r = 0.4 v = (π x r x r) x h v = (3.14 x 0.4 x 0.4) x h v = 0.5m^2 x 10m v = 5m^3 Inside = 5m^3 Outside = 7.8m^3 volume2 - volume1 = volume of culvert 7.8m^3 - 5m^3 = 2.8m^3 The concrete required to make the culvert is 2.8m^3 |
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